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The molar conductivity of 0.025 mol L^(-...

The molar conductivity of 0.025 mol `L^(-1)` methanoic acid is 46.1 S `cm^(2)` `mol^(-1)`. Calculate its degree of dissociation and dissociation constant. Given `v^(0)(H^(+))=349.6S" "cm^(2)mol^(-1) and lamda^(0)(HCOO^(-))=54.6S" "cm^(2)mol^(-1)`

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The correct Answer is:
`3.7 xx 10^(-4) mol L^(-1)`
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