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Pt|H(2)(1 atm )|H^(+)(0.001M)||H^(+)(0.1...

`Pt|H_(2)(1 atm )|H^(+)(0.001M)||H^(+)(0.1M)|H_(2)(1atm)|Pt` what will be the value of `E_(cell)` for this cell

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The correct Answer is:
`6.5 xx 10^(-4) M; 1.35 xx 10^(-5)`
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