An enzyme contains 2% of sulphur. The molecular weight of the Enzyme is 6400. How many sulphur atoms are present in that enzyme molecule?

Answer

To solve the problem, we need to find out how many sulfur atoms are present in the enzyme molecule given that it contains 2% sulfur and has a molecular weight of 6400.

### Step-by-Step Solution:

1. **Determine the mass of sulfur in the enzyme**:
- The enzyme has a molecular weight of 6400 g/mol.
- Since the enzyme contains 2% sulfur, we can calculate the mass of sulfur in one molecule of the enzyme.
- Mass of sulfur = (2/100) × Molecular weight of enzyme
- Mass of sulfur = (2/100) × 6400 = 128 g/mol

2. **Find the number of sulfur atoms**:
- The atomic mass of sulfur (S) is approximately 32 g/mol.
- To find the number of sulfur atoms in the enzyme, we divide the mass of sulfur by the atomic mass of sulfur.
- Number of sulfur atoms = Mass of sulfur / Atomic mass of sulfur
- Number of sulfur atoms = 128 g/mol / 32 g/mol = 4

### Final Answer:
The number of sulfur atoms present in one molecule of the enzyme is **4**.

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