X litre of carbon monoxide is present at STP. It is completely oxidised to`CO_2` formed is 11.207 L. What is the value of X in litres?

Options

A. 22.414
B. 11.207
C. 5.6035
D. 44.828

Answer

To solve the problem, we need to determine the volume of carbon monoxide (CO) that is completely oxidized to form carbon dioxide (CO₂) at standard temperature and pressure (STP).

### Step-by-Step Solution:

1. **Understanding the Reaction**:
The reaction for the complete oxidation of carbon monoxide (CO) to carbon dioxide (CO₂) can be written as:
\[ 2 \text{CO} + \text{O}_2 \rightarrow 2 \text{CO}_2 \]
This indicates that 2 volumes of CO react with 1 volume of O₂ to produce 2 volumes of CO₂.

2. **Applying Avogadro's Law**:
According to Avogadro's law, under the same conditions of temperature and pressure, equal volumes of gases contain an equal number of molecules. Therefore, the volume ratio of reactants and products is the same as the mole ratio.

3. **Volume Ratio**:
From the balanced equation, we see that:
- 2 volumes of CO produce 2 volumes of CO₂.
- This means the volume ratio of CO to CO₂ is 1:1.

4. **Given Data**:
We are given that the volume of CO₂ produced is 11.207 L.

5. **Finding the Volume of CO**:
Since the volume ratio of CO to CO₂ is 1:1, the volume of CO (denoted as X) that was oxidized to produce 11.207 L of CO₂ will also be:
\[ X = 11.207 \text{ L} \]

6. **Conclusion**:
Therefore, the value of X is:
\[ X = 11.207 \text{ L} \]

### Final Answer:
The value of X is **11.207 L**.

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