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Which of the following has number of mol...

Which of the following has number of molecules present equal to those present in 16 grams of oxygen

A

`16g O_(3)`

B

`32g SO_(2)`

C

`16gSO_(2)`

D

All the above

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining which substance has the same number of molecules as those present in 16 grams of oxygen, we will follow these steps: ### Step 1: Calculate the number of moles in 16 grams of oxygen (O₂). - The molecular mass of oxygen (O₂) is calculated as: \[ \text{Molecular mass of O}_2 = 2 \times 16 \, \text{g/mol} = 32 \, \text{g/mol} \] - Using the formula for moles: \[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} = \frac{16 \, \text{g}}{32 \, \text{g/mol}} = 0.5 \, \text{moles} \] ### Step 2: Determine the number of moles in each option provided. 1. **For 16 grams of ozone (O₃)**: - The molecular mass of ozone (O₃) is: \[ \text{Molecular mass of O}_3 = 3 \times 16 \, \text{g/mol} = 48 \, \text{g/mol} \] - Calculate the number of moles: \[ \text{Number of moles} = \frac{16 \, \text{g}}{48 \, \text{g/mol}} = \frac{1}{3} \, \text{moles} \] 2. **For 32 grams of sulfur dioxide (SO₂)**: - The molecular mass of sulfur dioxide (SO₂) is: \[ \text{Molecular mass of SO}_2 = 32 \, \text{g/mol (S)} + 2 \times 16 \, \text{g/mol (O)} = 64 \, \text{g/mol} \] - Calculate the number of moles: \[ \text{Number of moles} = \frac{32 \, \text{g}}{64 \, \text{g/mol}} = 0.5 \, \text{moles} \] 3. **For 16 grams of sulfur dioxide (SO₂)**: - Using the same molecular mass of SO₂: - Calculate the number of moles: \[ \text{Number of moles} = \frac{16 \, \text{g}}{64 \, \text{g/mol}} = \frac{1}{4} \, \text{moles} \] ### Step 3: Compare the number of moles. - From our calculations: - 16 grams of O₂ = 0.5 moles - 16 grams of O₃ = \( \frac{1}{3} \) moles - 32 grams of SO₂ = 0.5 moles - 16 grams of SO₂ = \( \frac{1}{4} \) moles ### Conclusion: The substance that has the same number of moles (and thus the same number of molecules) as 16 grams of oxygen is **32 grams of sulfur dioxide (SO₂)**.
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