0.1 moles of Hydrocaron on complete combustion produced 17.6 gms of `CO_(2)`. How many Carbon atoms are present in each molecule of the hydrocarbon.

Answer

To find out how many carbon atoms are present in each molecule of the hydrocarbon, we can follow these steps:

### Step 1: Understand the combustion of hydrocarbons
When a hydrocarbon (let's denote it as CₓHᵧ) undergoes complete combustion, it reacts with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O). The general reaction can be represented as:
\[ \text{C}_x\text{H}_y + \left( x + \frac{y}{4} \right) \text{O}_2 \rightarrow x \text{CO}_2 + \frac{y}{2} \text{H}_2\text{O} \]

### Step 2: Relate moles of hydrocarbon to moles of CO₂ produced
From the combustion equation, we can see that 1 mole of the hydrocarbon produces x moles of CO₂. Therefore, if we know the number of moles of CO₂ produced, we can find the value of x (the number of carbon atoms in the hydrocarbon).

### Step 3: Calculate the number of moles of CO₂ produced
We are given that 0.1 moles of the hydrocarbon produce 17.6 grams of CO₂. To find the number of moles of CO₂ produced, we first need to calculate the molar mass of CO₂:
- Molar mass of CO₂ = 12 (C) + 2 × 16 (O) = 44 g/mol

Now, we can calculate the number of moles of CO₂ produced:
\[ \text{Number of moles of CO}_2 = \frac{\text{mass of CO}_2}{\text{molar mass of CO}_2} = \frac{17.6 \text{ g}}{44 \text{ g/mol}} = 0.4 \text{ moles} \]

### Step 4: Relate moles of CO₂ to moles of hydrocarbon
Since 0.1 moles of hydrocarbon produce 0.4 moles of CO₂, we can find out how many moles of CO₂ would be produced by 1 mole of hydrocarbon:
\[ \text{Moles of CO}_2 \text{ produced by 1 mole of hydrocarbon} = 0.4 \text{ moles} \div 0.1 \text{ moles} = 4 \text{ moles} \]
This means that 1 mole of the hydrocarbon produces 4 moles of CO₂, indicating that x = 4.

### Step 5: Conclusion
Thus, the number of carbon atoms present in each molecule of the hydrocarbon is 4.

### Final Answer
**There are 4 carbon atoms in each molecule of the hydrocarbon.**

---