Home
Class 12
CHEMISTRY
The oxidation number and covalency of su...

The oxidation number and covalency of sulphur in the sulphur molecule `(S_(8))` are

A

0 and 2

B

`+6` and 8

C

0 and 8

D

`+6` and 2

Text Solution

AI Generated Solution

The correct Answer is:
To determine the oxidation number and covalency of sulfur in the sulfur molecule \( S_8 \), we can follow these steps: ### Step 1: Determine the Oxidation Number - In the molecule \( S_8 \), sulfur is in its elemental state. - The oxidation number of an element in its standard state is always zero. - Therefore, the oxidation number of sulfur in \( S_8 \) is **0**. ### Step 2: Determine the Covalency - Covalency refers to the number of bonds an atom can form with other atoms. - In the \( S_8 \) molecule, sulfur atoms are arranged in a crown-like structure where each sulfur atom is bonded to two other sulfur atoms. - Each sulfur atom forms **2 covalent bonds** with its neighboring sulfur atoms. - Thus, the covalency of sulfur in \( S_8 \) is **2**. ### Final Answer - The oxidation number of sulfur in \( S_8 \) is **0** and the covalency is **2**.
Promotional Banner

Similar Questions

Explore conceptually related problems

Sulphur molecule is

The oxidation number of sulphur in H_(2)S_(2)O_(8) is:

What is the maximum covalency of sulphur?

Oxidation number of sulphur in Na_(2)S_(2)O_(3) is

What is the oxidation state of sulphur in sulphate ion ?

The oxidation numbers of the sulphur atoms in pcroxy- monosulphuric acid (H_(2)SO_(5)) and peroxydisulphuric acid (H_(2)S_(2)O_(8)) are respectively.

Find the oxidation number of sulphur in the following compounds: H_(2)S,H_(2)SO_(4),S_(2)O_(4)^(2-),S_(2)O_(8)^(2-),HSO_(3)^(ө) .

The hybridisation of sulphur in sulphur dioxide is

When SO_2 is passed into an acidified potassium dichromate solution, the oxidation numbers of sulphur and chromium in the final products respectively are :

What is the oxidation number of Sulphur in Na_(2)SO_(3) molecule ?