The number of moles of `MnO_(4)^(-)` and `Cr_(2)O_(7)^(-2)` separately required to oxidise 1 mole of `FeC_(2)O_(4)` each in acidic medium respectively

Options

A. `0.5,0.6`
B. `0.6,0.4`
C. `0.4,0.5`
D. `0.6,0.5`

Answer

To determine the number of moles of \( \text{MnO}_4^{-} \) and \( \text{Cr}_2\text{O}_7^{2-} \) required to oxidize 1 mole of \( \text{FeC}_2\text{O}_4 \) in acidic medium, we need to balance the relevant chemical reactions.

### Step 1: Reaction of \( \text{MnO}_4^{-} \) with \( \text{FeC}_2\text{O}_4 \)

1. Write the unbalanced equation:
\[ \text{MnO}_4^{-} + \text{FeC}_2\text{O}_4 \rightarrow \text{Mn}^{2+} + \text{Fe}^{3+} + \text{CO}_2 + \text{H}_2\text{O} \]

2. Balance the equation in acidic medium:
- The balanced equation is:
\[ 3 \text{MnO}_4^{-} + 5 \text{FeC}_2\text{O}_4 + 24 \text{H}^{+} \rightarrow 3 \text{Mn}^{2+} + 5 \text{Fe}^{3+} + 10 \text{CO}_2 + 12 \text{H}_2\text{O} \]

3. From the balanced equation, we see that:
- 5 moles of \( \text{FeC}_2\text{O}_4 \) react with 3 moles of \( \text{MnO}_4^{-} \).
- Therefore, for 1 mole of \( \text{FeC}_2\text{O}_4 \):
\[ \text{Moles of } \text{MnO}_4^{-} = \frac{3}{5} = 0.6 \text{ moles} \]

### Step 2: Reaction of \( \text{Cr}_2\text{O}_7^{2-} \) with \( \text{FeC}_2\text{O}_4 \)

1. Write the unbalanced equation:
\[ \text{Cr}_2\text{O}_7^{2-} + \text{FeC}_2\text{O}_4 \rightarrow \text{Cr}^{3+} + \text{Fe}^{3+} + \text{CO}_2 + \text{H}_2\text{O} \]

2. Balance the equation in acidic medium:
- The balanced equation is:
\[ \text{Cr}_2\text{O}_7^{2-} + 2 \text{FeC}_2\text{O}_4 + 14 \text{H}^{+} \rightarrow 2 \text{Cr}^{3+} + 2 \text{Fe}^{3+} + 4 \text{CO}_2 + 7 \text{H}_2\text{O} \]

3. From the balanced equation, we see that:
- 2 moles of \( \text{FeC}_2\text{O}_4 \) react with 1 mole of \( \text{Cr}_2\text{O}_7^{2-} \).
- Therefore, for 1 mole of \( \text{FeC}_2\text{O}_4 \):
\[ \text{Moles of } \text{Cr}_2\text{O}_7^{2-} = \frac{1}{2} = 0.5 \text{ moles} \]

### Final Answer
- The number of moles of \( \text{MnO}_4^{-} \) required to oxidize 1 mole of \( \text{FeC}_2\text{O}_4 \) is **0.6 moles**.
- The number of moles of \( \text{Cr}_2\text{O}_7^{2-} \) required to oxidize 1 mole of \( \text{FeC}_2\text{O}_4 \) is **0.5 moles**.