One mole of hydrazine loses 10 moles of electrons. If all the hydrogen content is present in the product, the oxidation number of nitrogen in product is +x. What is value of x.

Answer

To find the oxidation number of nitrogen in the product after one mole of hydrazine (N2H4) loses 10 moles of electrons, we can follow these steps:

### Step 1: Determine the oxidation state of nitrogen in hydrazine (N2H4).
The formula for hydrazine is N2H4. To find the oxidation state of nitrogen (N) in hydrazine, we can set up the equation based on the overall charge of the molecule, which is neutral (0).

Let the oxidation state of nitrogen be \( x \). In hydrazine:
- There are 2 nitrogen atoms, contributing \( 2x \).
- There are 4 hydrogen atoms, each with an oxidation state of +1, contributing \( 4 \times (+1) = +4 \).

Setting up the equation:
\[ 2x + 4 = 0 \]

### Step 2: Solve for x.
Rearranging the equation gives:
\[ 2x = -4 \]
\[ x = -2 \]

Thus, the oxidation state of nitrogen in hydrazine (N2H4) is -2.

### Step 3: Analyze the loss of electrons.
According to the question, one mole of hydrazine loses 10 moles of electrons. This indicates that the nitrogen atoms are being oxidized.

### Step 4: Determine the change in oxidation state.
Each nitrogen atom in hydrazine starts with an oxidation state of -2. If the total loss of electrons is 10 moles, we can determine how many moles of nitrogen are involved in this oxidation.

Since there are 2 nitrogen atoms in hydrazine, the total change in oxidation state for both nitrogen atoms can be calculated as follows:
- Each nitrogen atom loses electrons, which increases its oxidation state.

### Step 5: Calculate the new oxidation state.
The total change in oxidation state for 2 nitrogen atoms losing 10 moles of electrons can be calculated as:
- The total increase in oxidation state = 10 moles of electrons / 2 nitrogen atoms = 5 moles of electrons per nitrogen atom.

Thus, the new oxidation state of nitrogen after losing 5 electrons (from -2) becomes:
\[ -2 + 5 = +3 \]

### Conclusion:
The oxidation number of nitrogen in the product is +3.

### Final Answer:
The value of \( x \) is +3.

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