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4Mg+10HNO(3)to4Mg(NO(3))(2)+NH(4)NO(3)+3...

`4Mg+10HNO_(3)to4Mg(NO_(3))_(2)+NH_(4)NO_(3)+3H_(2)O`. In this reaction

A

96 gms magnesium can reduce one mole of `HNO_(3)`

B

Equivalent weight of reduced `HNO_(3)` is `1/8` of its molecular weight

C

Entire `HNO_(3)` involved in the reaction is reduced

D

`HNO_(3)` is reduced to the best possible extent

Text Solution

AI Generated Solution

The correct Answer is:
To analyze the given reaction and determine the correctness of the statements about it, we will follow a systematic approach. ### Step-by-Step Solution: 1. **Write the Balanced Reaction:** The balanced chemical reaction is: \[ 4 \text{Mg} + 10 \text{HNO}_3 \rightarrow 4 \text{Mg(NO}_3\text{)}_2 + \text{NH}_4\text{NO}_3 + 3 \text{H}_2\text{O} \] 2. **Determine Oxidation States:** - In HNO₃, nitrogen (N) has an oxidation state of +5. - In NH₄NO₃, nitrogen in the ammonium ion (NH₄⁺) has an oxidation state of -3. - The nitrogen in the product Mg(NO₃)₂ remains +5. 3. **Identify Redox Changes:** - The nitrogen in HNO₃ (oxidation state +5) is reduced to -3 in NH₄NO₃. - Therefore, the nitrogen in HNO₃ is undergoing reduction. 4. **Calculate the Amount of Magnesium:** - The molecular weight of magnesium (Mg) is 24 g/mol. - Since 4 moles of magnesium react with 10 moles of HNO₃, we can calculate the mass of magnesium required to reduce 1 mole of HNO₃: \[ 4 \text{ moles of Mg} = 4 \times 24 \text{ g} = 96 \text{ g} \] Hence, 96 g of magnesium will reduce 1 mole of HNO₃. 5. **Determine Equivalent Weight of Reduced HNO₃:** - The change in oxidation state for nitrogen in HNO₃ is from +5 to -3, which is a change of 8. - The equivalent weight of HNO₃ can be calculated as: \[ \text{Equivalent weight} = \frac{\text{Molecular weight}}{\text{Number of electrons transferred}} = \frac{\text{Molecular weight}}{8} \] Thus, the equivalent weight of reduced HNO₃ is indeed 1/8 of its molecular weight. 6. **Evaluate Statements:** - **Statement 1:** "4 moles of magnesium reduce 1 mole of HNO₃." - **Correct** - **Statement 2:** "Equivalent weight of reduced HNO₃ is 1/8 of its molecular weight." - **Correct** - **Statement 3:** "Entire HNO₃ involved in this reaction is reduced." - **Incorrect** (only part of it is reduced) - **Statement 4:** "HNO₃ is reduced to the best possible extent." - **Correct** (as -3 is the lowest oxidation state for nitrogen) ### Final Conclusion: The correct statements are 1, 2, and 4.
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