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The temperature of a gas is increased by...

The temperature of a gas is increased by 1 °C. Then from the following statements pickout the correct one
1) The volume increases by 1/273 of its volume at 0°C at constant pressure
2) The pressure increases by 1/273 of its pressure at 0°C at constant volume
3) The volume decreases by 1/273 of its volume at 0°C
4) The pressure is doubled to its pressure at 0°C

A

1,3

B

3,4

C

1,2

D

2,3

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the statements provided regarding the behavior of a gas when its temperature is increased by 1 °C. We will use the principles of gas laws, specifically Charles's Law and Gay-Lussac's Law. ### Step-by-Step Solution: 1. **Understanding the Context**: - We are dealing with a gas whose temperature is increased by 1 °C. We need to determine the effects on volume and pressure based on the given statements. 2. **Applying Charles's Law**: - Charles's Law states that at constant pressure, the volume of a gas is directly proportional to its absolute temperature (in Kelvin). - The absolute temperature at 0 °C is 273 K. When the temperature is increased by 1 °C, the new temperature becomes 1 °C, which is 274 K. - The change in volume can be expressed as: \[ V_1 = V_0 \left(1 + \frac{1}{273}\right) \] - This means the volume increases by \( \frac{1}{273} \) of its volume at 0 °C at constant pressure. - **Conclusion**: Statement 1 is correct. 3. **Applying Gay-Lussac's Law**: - Gay-Lussac's Law states that at constant volume, the pressure of a gas is directly proportional to its absolute temperature. - The pressure at 0 °C is \( P_0 \) (at 273 K), and at 1 °C (274 K), the pressure can be expressed as: \[ P_1 = P_0 \left(1 + \frac{1}{273}\right) \] - This indicates that the pressure increases by \( \frac{1}{273} \) of its pressure at 0 °C at constant volume. - **Conclusion**: Statement 2 is correct. 4. **Analyzing Statement 3**: - The statement claims that the volume decreases by \( \frac{1}{273} \) of its volume at 0 °C. This is incorrect because, as we established from Charles's Law, the volume actually increases with an increase in temperature. - **Conclusion**: Statement 3 is incorrect. 5. **Analyzing Statement 4**: - The statement claims that the pressure is doubled to its pressure at 0 °C. This is also incorrect as we derived from Gay-Lussac's Law that the pressure increases but does not double with a 1 °C increase. - **Conclusion**: Statement 4 is incorrect. ### Final Answer: The correct statements are: 1) The volume increases by \( \frac{1}{273} \) of its volume at 0 °C at constant pressure. 2) The pressure increases by \( \frac{1}{273} \) of its pressure at 0 °C at constant volume.
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