Home
Class 12
CHEMISTRY
At Boyle temperature...

At Boyle temperature

A

the effects of the repulsive and atractive intermolecular forces just cancelled each other

B

the repulsive intermolecular forces are greater than the attractive intermolecular forces

C

the repulsive intermolecular forces are less than the attractive intermolecular forces

D

`b-a/(RT) gt 0`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The ratio of the inversion temperature of a gas to its Boyle temperature is

Calculate Boyle temperature range for CO_(2) if its van der Waal's constants a and b are 3.592 atm "litre"^(2)" mole"^(2) and b =0.0427" litre mole"^(-1) .

The volume to be excluded due to only two molecules of a gas in collision with a fixed point of impact is 0.09 l mol^(-1) . If the value of 'a' is 3.6 atm L^(2) mol^(-2) , Calculate Boyle temperature. (R = 0.08 L atm K^(-1) m^(-1) )

What is Boyle's temperature?

The Boyle temperature for real gases is given by :

The ratio of Boyle's temperature and critical temperature for a gas is:

The Critical temperature , Boyle's temperature and inversion temperature respectively are given as

At Boyle's temperature , compressibility factor Z for a real gas is

If the critical temperature of a gas is 300 K then the ratio of its inversion and Boyle's temperature will be

The Boyle temperature of three gases are given in the table : {:("Gas","Boyle Temperature (K)",), ("Ethene",735,), ("Oxygen",400,), ("Hydrogen",110,) :} If the compressibility factor was measured at 400 K, the gases are :