Home
Class 12
CHEMISTRY
Change in volume of the system does not ...

Change in volume of the system does not alter the number of moles in which of the following equilibrium?

A

`N_(2(g)) + O_(2(g)) hArr 2 NO_((g))`

B

`PCI_(5(g)) hArr PCI_(3(g)) + Cl_(2(g)) `

C

`N_(2(g)) + 3H_(2(g)) hArr 2 NH_(3(g))`

D

`SO_(2) Cl_(2(g)) hArr SO_(2(g)) + Cl_(2(g))`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which equilibrium is not affected by a change in volume, we need to analyze the number of moles of reactants and products in each equilibrium reaction provided. ### Step-by-Step Solution: 1. **Identify the Equilibria**: We have four equilibrium reactions to analyze. - Reaction 1: A + B ⇌ C + D - Reaction 2: PCl5 ⇌ PCl3 + Cl2 - Reaction 3: N2 + 3H2 ⇌ 2NH3 - Reaction 4: SO2Cl2 ⇌ SO2 + Cl2 2. **Count Moles for Each Reaction**: - **Reaction 1**: Let's assume A + B ⇌ C + D has 2 moles on both sides (1 mole of A + 1 mole of B = 2 moles; 1 mole of C + 1 mole of D = 2 moles). - **Reaction 2**: PCl5 ⇌ PCl3 + Cl2 has 1 mole on the left (PCl5) and 2 moles on the right (PCl3 + Cl2). - **Reaction 3**: N2 + 3H2 ⇌ 2NH3 has 4 moles on the left (1 mole of N2 + 3 moles of H2) and 2 moles on the right (2 moles of NH3). - **Reaction 4**: SO2Cl2 ⇌ SO2 + Cl2 has 1 mole on the left (SO2Cl2) and 2 moles on the right (SO2 + Cl2). 3. **Determine Change in Moles with Volume Change**: - For a reaction where the number of moles of reactants equals the number of moles of products, a change in volume will not affect the equilibrium position significantly because the ratio of moles remains constant. - In **Reaction 1**, the number of moles is equal on both sides (2 moles), so a change in volume will not alter the number of moles. - In **Reaction 2**, **Reaction 3**, and **Reaction 4**, the number of moles differs between reactants and products, meaning a change in volume will affect the equilibrium position. 4. **Conclusion**: The only reaction where the change in volume does not alter the number of moles is **Reaction 1**. ### Final Answer: The change in volume of the system does not alter the number of moles in **Reaction 1** (A + B ⇌ C + D).
Doubtnut Promotions Banner Mobile Dark
|

Similar Questions

Explore conceptually related problems

In which of the following equilibrium ,change in volume of the system does not alter the number of moles:

In which of following reactions, increase in the volume at constant temperature does not affect the number of moles of at equilibrium?

Starting with one moles of O_(2) and two moles of SO_(2) , the equilibrium for the formation of SO_(3) was established at a certain temperature. If V is the volume of the vessel and 2 x is the number of moles of SO_(3) present, the equilibrium cosntant will be

By adding inert gas at a constant volume, which of the following equilibrium will not be affected?

For a reversible system at equilibrium, which of the following is correct

A : A catalyst does not alter the equilibrium constant of a reaction R : A catalyst does not alter the position of chemical equilibrium .

Hydrogen (a moles ) and iodine (b moles ) react to give 2x moles of the HI at equilibrium . The total number of moles at equilibrium is

One mole of H_(2) and 2 moles of I_(2) are taken initially in a two litre vessel. The number of moles of H_(2) at equilibrium is 0.2. Then the number of moles of I_(2) and HI at equilibrium is

When light is refracted which of the following does not change?

For the following equilibrium, 2SO_(2)(g) +O_(2)(g) hArr 2SO_(3)(g) the total equilibrium pressure is P_(1) . If volume of the system is reduced to 1//2 of this initial volume then equilibrium is restablished. The new equilibrium total pressure will be :

Home
Profile