Home
Class 12
CHEMISTRY
The equilibrium constant K(p) for the re...

The equilibrium constant `K_(p)` for the reaction `H_(2)(g)+I_(2)(g) hArr 2HI(g)` changes if:

A

`"mole"^(-1)` lit

B

`mot^(-2)` litre

C

mole `lit^(-1)`

D

no units

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

At 448^(@)C , the equilibrium constant (K_(c)) for the reaction H_(2)(g)+I_(2)(g) hArr 2HI(g) is 50.5 . Predict the direction in which the reaction will proceed to reach equilibrium at 448^(@)C , if we start with 2.0xx10^(-2) mol of HI, 1.0xx10^(-2) mol of H_(2) and 3.0xx10^(-2) mol of I_(2) in a 2.0 L container.

The value of the equilibrium constant for the reaction : H_(2) (g) +I_(2) (g) hArr 2HI (g) at 720 K is 48. What is the value of the equilibrium constant for the reaction : 1//2 H_(2)(g) + 1//2I_(2)(g) hArr HI (g)

The equilibrium constant for the reaction H_(2)(g)+I_(2)(g)hArr 2HI(g) is 32 at a given temperature. The equilibrium concentration of I_(2) and HI are 0.5xx10^(-3) and 8xx10^(-3)M respectively. The equilibrium concentration of H_(2) is

Suppose the value of the equilibrium constant for the given reaction H_2(g) + I_(2)(g) hArr 2HI(g) at 717 K is 64, then calculate the same (eq. const.) for the reaction HI hArr 1/2 H_2 + 1/2 I_2 .

If the equilibrium constant of the reaction 2HIhArr H_(2)+I_(2) is 0.25, then the equilibrium constant for the reaction, H_(2)(g)+I_(2)(g)hArr 2HI(g) would be

The value of the equilibrium constant K for the reaction H_2(g) +I_2(g) hArr 2Hl(g) " is " 48 " at " 717 K. Find out the value of K for the following reaction at Hl(g) hArr (1)/(2) H_2(g) + (1)/(2) I_2(g)

The equilbrium constant of the reaction H_(2)(g)+I_(2)(g)hArr 2HI(g) is 50. If the volume of the container is reduced to half of its original value, the value of equilibrium constant will be

The equilibrium constant of the reaction H_(2)(g)+I_(2)(g)hArr2HI(g) at 426^(@)C is 55.3 , what will be the value of equilibrium constant a. if the reaction is reversed and b. if the given reaction is represented as 3H_(2)+3I_(2)hArr6HI ?

The equilibrium constant at 717 K for the reaction: H_(2(g))+I_(2(g))lArr2HI_((g)) is 50. The equilibrium constant for the reaction: 2HI_(2(g))lArrH_(2(g))+I_(2(g)) is

The equilibrium constant of the following reactions at 400 K are given: 2H_(2)O(g) hArr 2H_(2)(g)+O_(2)(g), K_(1)=3.0xx10^(-13) 2CO_(2)(g) hArr 2CO(g)+O_(2)(g), K_(2)=2xx10^(-12) Then, the equilibrium constant K for the reaction H_(2)(g)+CO_(2)(g) hArr CO(g)+H_(2)O(g) is