`SO_(2) Cl_(2) hArr SO_(2) + Cl_(2) ("gaseous") , PCl_(5) hArr PCl_(x) + Cl_(2)` (gaseous ) If some `SO_(2)` is removed from the above set of equillibria ocuring in same closed container ____

Options

A. Degree of dissociation of` SO_(2)C1_(2)` decreases
B. Degree of dissociation of `PCl_(5)` decreases
C. Degree of dissociation of`SO_(2) Cl_(2)` increases
D. Concentration of `PCl_(3)` decreases

Answer

To solve the problem, we need to analyze the two equilibria present in the closed container and how the removal of some \( SO_2 \) affects them according to Le Chatelier's principle.

### Step-by-Step Solution:

1. **Identify the Equilibria:**
- The first equilibrium is:
\[ SO_2Cl_2 \rightleftharpoons SO_2 + Cl_2 \]
- The second equilibrium is:
\[ PCl_5 \rightleftharpoons PCl_3 + Cl_2 \]

2. **Understand the Effect of Removing \( SO_2 \):**
- According to Le Chatelier's principle, if a system at equilibrium is disturbed, the system will shift in a direction that counteracts the disturbance.
- In this case, removing \( SO_2 \) decreases the concentration of one of the products in the first equilibrium.

3. **Shift in the First Equilibrium:**
- Since \( SO_2 \) is a product of the first equilibrium, removing it will cause the equilibrium to shift to the right to produce more \( SO_2 \) and \( Cl_2 \).
- This means that more \( SO_2Cl_2 \) will dissociate, leading to an **increase in the degree of dissociation of \( SO_2Cl_2 \)**.

4. **Effect on the Concentration of \( Cl_2 \):**
- As \( SO_2Cl_2 \) dissociates to form more \( SO_2 \) and \( Cl_2 \), the concentration of \( Cl_2 \) will also increase.

5. **Shift in the Second Equilibrium:**
- The increase in \( Cl_2 \) concentration will affect the second equilibrium:
\[ PCl_5 \rightleftharpoons PCl_3 + Cl_2 \]
- According to Le Chatelier's principle, an increase in the concentration of a product (\( Cl_2 \)) will shift the equilibrium to the left, suppressing the dissociation of \( PCl_5 \).
- Therefore, the **degree of dissociation of \( PCl_5 \) will decrease**.

### Conclusion:
- The removal of \( SO_2 \) leads to an increase in the degree of dissociation of \( SO_2Cl_2 \) and a decrease in the degree of dissociation of \( PCl_5 \).

### Final Answer:
- **Degree of dissociation of \( SO_2Cl_2 \) increases.**
- **Degree of dissociation of \( PCl_5 \) decreases.**