Yield of Ammonia will be more in Haber's process under _____ conditions (L = Low, H = high T = Temp, p = Pressure )

Options

A. LT , LP
B. LT , HP
C. HT, HP
D. HT, LP

Answer

To determine the conditions under which the yield of ammonia will be more in the Haber process, we need to analyze the reaction and its characteristics.

### Step-by-Step Solution:

1. **Understand the Haber Process**: The Haber process synthesizes ammonia (NH₃) from nitrogen (N₂) and hydrogen (H₂) gases. The balanced chemical equation for the reaction is:
\[ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) \]

2. **Identify the Nature of the Reaction**: This reaction is exothermic, meaning it releases heat. The enthalpy change (ΔH) for the reaction is negative (approximately -92 kJ/mol).

3. **Analyze the Effect of Temperature**:
- According to Le Chatelier's principle, if the temperature is decreased, the equilibrium will shift towards the exothermic direction to produce more heat.
- Therefore, lower temperatures favor the formation of ammonia.

4. **Analyze the Effect of Pressure**:
- The reaction involves a decrease in the number of moles of gas (from 4 moles of reactants to 2 moles of product).
- Increasing the pressure will shift the equilibrium towards the side with fewer moles of gas, which is the product side (ammonia).
- Thus, higher pressures favor the formation of ammonia.

5. **Conclusion**:
- To maximize the yield of ammonia in the Haber process, the conditions should be low temperature and high pressure.
- Therefore, the answer to the question is: **Yield of Ammonia will be more in Haber's process under Low Temperature and High Pressure conditions (L, H)**.

### Final Answer:
The yield of ammonia will be more in Haber's process under **Low Temperature and High Pressure (L, H)** conditions.