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In the dissociation of CaCO(3) in a clos...

In the dissociation of `CaCO_(3)` in a closed vessel, the forward reaction is favoured by

A

adding some more` CaCO_(3)`

B

removing some CaO

C

increasing the pressure

D

removing `CO_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the dissociation of calcium carbonate (CaCO₃) in a closed vessel, we need to analyze the reaction and apply Le Chatelier's principle. ### Step-by-Step Solution: 1. **Identify the Reaction**: The dissociation of calcium carbonate can be represented as: \[ \text{CaCO}_3 (s) \rightleftharpoons \text{CaO} (s) + \text{CO}_2 (g) \] Here, solid calcium carbonate dissociates into solid calcium oxide and gaseous carbon dioxide. 2. **Understand the System**: In a closed vessel, the reaction reaches a state of equilibrium where the rate of the forward reaction (dissociation of CaCO₃) equals the rate of the reverse reaction (formation of CaCO₃ from CaO and CO₂). 3. **Apply Le Chatelier's Principle**: Le Chatelier's principle states that if a system at equilibrium is subjected to a change in concentration, pressure, or temperature, the system will adjust to counteract that change and restore a new equilibrium. 4. **Analyze the Options**: - **Adding more CaCO₃**: This would not favor the forward reaction since it would increase the concentration of the solid reactant, but solids do not affect the equilibrium position. - **Removing some CaO**: This would not significantly affect the equilibrium since CaO is a solid and does not change the concentration of gases in the system. - **Increasing the pressure**: This would favor the side with fewer moles of gas. In this case, since we have one mole of CO₂ gas produced, increasing the pressure would not favor the forward reaction. - **Removing CO₂**: This would decrease the concentration of one of the products (CO₂), causing the equilibrium to shift to the right (forward direction) to produce more CO₂. 5. **Conclusion**: Based on the analysis, the forward reaction (dissociation of CaCO₃) is favored by **removing CO₂** from the system. This is because it reduces the concentration of the product, prompting the equilibrium to shift towards the right to produce more CO₂. ### Final Answer: The forward reaction is favored by **removing CO₂** from the equilibrium mixture.
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