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The reaction Quotient (Q) predicts:...

The reaction Quotient (Q) predicts:

A

The direction of equilibrium to be attained

B

The ratio of activities at equilibrium ie., `K_(c)`

C

he ratio of activities at equilibrium i.e., `K_(c)`

D

All of these

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To solve the question regarding what the reaction quotient (Q) predicts, we can follow these steps: ### Step 1: Understand the Reaction Quotient (Q) The reaction quotient (Q) is a ratio that compares the concentrations of products to the concentrations of reactants at any point in time during a chemical reaction. It is calculated using the same expression as the equilibrium constant (K), but it can be applied to any set of concentrations, not just at equilibrium. ### Step 2: Compare Q with the Equilibrium Constant (K) The value of Q can be compared to the equilibrium constant (K) to determine the direction in which the reaction will proceed: - If Q < K, the reaction will proceed in the forward direction (toward products). - If Q > K, the reaction will proceed in the reverse direction (toward reactants). - If Q = K, the reaction is at equilibrium, and no net change will occur. ### Step 3: Determine the Implications of Q The reaction quotient helps predict: - The direction of the reaction (forward or reverse). - The extent to which the reaction will proceed to reach equilibrium. - Whether the system is at equilibrium or not. ### Step 4: Analyze the Given Options The question states that Q predicts "amount" related to the reaction. Since Q helps in determining the direction of the reaction and its relationship to K, we can conclude that it aids in predicting the behavior of the system. ### Conclusion Based on the understanding of Q and its comparison to K, we can conclude that the reaction quotient predicts the direction in which the reaction will likely proceed. Therefore, if all options provided in the question are correct, the answer would be that Q predicts all of the above. ### Final Answer The correct answer is that the reaction quotient (Q) predicts the direction in which the reaction will likely proceed, and all of the options given are correct. ---
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