Home
Class 12
CHEMISTRY
In the dissociation of 2HI hArr H(2)+I(2...

In the dissociation of `2HI hArr H_(2)+I_(2)`, the degree of dissociation will be affected by

A

Addition of inert gas

B

Addition of `H_(2) ` of `I_(2)`

C

Increase of temperature

D

Increase of pressuree

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

What is degree of dissociation?

For the dissociation reaction N_(2)O_(4) (g)hArr 2NO_(2)(g) , the degree of dissociation (alpha) interms of K_(p) and total equilibrium pressure P is:

Explain the term degree of dissociation.

If degree of dissociation of 2M CH_3 COOH is 10% then degree of dissociation of this acetic acid in 3 Molar CH_3 COONa solution will be

Degree of dissociation is represented by the letter

For a reaction nA hArr A_n , degree of dissociation when A trimerises is

In the dissociation of PCl_(5) as PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) If the degree of dissociation is alpha at equilibrium pressure P, then the equilibrium constant for the reaction is

At 1000K , the pressure of iodine gas is found to be 0.1 atm due to partial dissociation of I_(2)(g) into I(g) . Had there been no dissociation, the pressure would have been 0.07 atm . Calculate the value of K_(p) for the reaction: I_(2)(g)hArr2I(g) .

At 1000K, the pressure of iodine gas is found to be 0.112 atm due to partial dissociation of I_(2)(g) into I(g). Had there been no dissociation, the pressure would have been 0.074 atm. Calculate the value of K_(p) for the reaction: I_(2)(g) hArr 2I(g) .

For the reaction N_(2)O_(4)(g)hArr2NO_(2)(g) , the degree of dissociation at equilibrium is 0.2 at 1 atm pressure. The equilibrium constant K_(p) will be