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The rate constant of a reaction is 1.5x...

The rate constant of a reaction is `1.5xx10^7 s^(-1) " at" 50^@C and 4.5xx10^7 s^(-1) " at " 100^@C` . Calculate the value of activation energy, `E_a` for the reaction.

Text Solution

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The ratio of specific rates at two different temperatuer are given as ,
`log = (K_(2))/(k_(1)) = (E_(a))/(2.303R) [(T_(2) - T_(1))/(T_(1)T_(2))]`
Substituting the values `K_(1),k_(2),T_(1),T_(2)` and molar gas constant R
` 0.301 = (E_(a) xx 1000)/(2.303 xx 8.314) xx (10)/(300 xx 310)`
Energy of activation ` = E_(a) = 53 KJ mol^(-1)`
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