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An increase in temperature by 10^(@) , ...

An increase in temperature by `10^(@)` , can increase the number of collisions only by 2% , but the rate of reaction increases by 100%. Why?

Text Solution

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Temperature is directly proportional to kinetic energy. Number of collisions is proportional to velcoity or square root of temperature .
However , in the Arrhenius rate expression, rate increases exponentially but not linearly, with a change in temperature . The number of molecules exceeding the activation energy approoxid double by a `10^(@)` rise in temperature . Hence rate increase by 100%.
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