When rate is plotted vs `(a -x)^n`, a straight line is obtained with positive slope, passing through orgin. Draw the graphs and discuss.

The position-time graph of a moving particle is a straight line inclined with time axis and passing through origin, therefore

The graph of the conic x^2-(y-1)^2=1 has one tangent line with positive slope that passes through the origin . The point of the tangency being (a,b) then find the value of sin^-1(a/b)

While stud dying the dependence of potential difference (V) across a resistor on the current (I) passing through it, in order to determine the resistance of the resistor, a student took 5 readings for different values of current and plotted a graph between V and I. He got a straight line graph passing through the origin. What does the straight line signify? Write the method of determining resistance of the resistor using this graph.

Rate constant k of a reaction varies with temperature according to the equation logk = constant -E_a/(2.303R)(1/T) where E_a is the energy of activation for the reaction . When a graph is plotted for log k versus 1/T , a straight line with a slope - 6670 K is obtained. Calculate the energy of activation for this reaction

Slope of the straight line obtained by plotting log_(10) k against 1/T represents what term ?

Find the equation of the straight line passing through the point (6,2) and having slope -3.

Find the equation of a straight line passing through (4,5) having slope 1