Home
Class 12
CHEMISTRY
Compute the heat of formation of liquid ...

Compute the heat of formation of liquid methyl alcohol in kilojoule per mol using the following data. Heat of vaporisation of liquid methyl alcohol `=38kJ//mol`. Heat of formation of gaseous atoms from the elements in their standard states `:H=218kJ // mol, C=715kJ //mol, O=249kJ //mol.`
Average bond energies`:`
`C-H415kJ//mol, C-O 356kJ//mol, O-H 463kJ //mol.`

Promotional Banner

Similar Questions

Explore conceptually related problems

Compute the heat of formation of liquid methyl alcohol in kilojoules per mole, using the following data. Heat of vapourisation of liquid methyl alcohol= 38 kJ/mol. Heat of formation of gaseous atoms from the elements in their standard states, H= 218kJ/mol, C= 715 kJ/mol, O= 249 kJ/mol. Average bond energies, C-H = 415 kJ/mol, C-O = 365 kJ/mol, O-H= 463 kJ/mol

the heat evolved in physisorption lies in the range (in kJ/mol) of :

Calculate heat of atomization of furan using the data Heats of atomization of C,H,O are 717,218,249 KJ"mol"^(-1) each.

the heat evolved in chemisoption lies in the range (in kJ/mol) of :

Calculate the enthalpy of formation of ammonia from the following bond energy data: (N-H) bond = 389 kJ mol^(-1), (H-H) bond = 435 kJ mol^(-1) , and (N-=N)bond = 945.36kJ mol^(-1) .

2.1g of Fe combines with S evolving 3.77KJ . The heat of formation of FeS in KJ//mol is

The entropy change for vapourisation of liquid water to steam 100^@C is …. JK^(-1) mol^(-1) . Given that heat of vapourisation is 40.8 kJ mol^(-1) .

Heat of neutralisation of NaOH and HCl is -57.46 kJ // equivalent. The heat of ionisation of water in kJ //mol is :

If the enthalpy of formation of H_2O(l) is -x kj/mol and enthalpy of neutralization of HCl and NaOH is -y kj/mol then enthalpy of formation of OH^-1 ion (in kJ/mol) is

The enthalpy of formation of H_(2)O(l) is -280.70 kJ/mol and enthalpy of neutralisation of a strong acid and strong base is -56.70 kJ/mol. What is the enthalpy of formation of OH^(-) ions?