Dissociation of `CH_(3)`,COOH is supressed by adding

Options

A. HCI
B. `H_(2)SO_(4)`
C. `CH_(3)COONa`
D. Any of the above

Answer

To solve the question regarding the suppression of the dissociation of acetic acid (CH₃COOH), we can follow these steps:

### Step 1: Understand the Dissociation of Acetic Acid
Acetic acid (CH₃COOH) dissociates in water according to the following equilibrium reaction:
\[ \text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+ \]

### Step 2: Identify the Effect of Adding Sodium Acetate
When sodium acetate (CH₃COONa) is added to the solution, it dissociates completely in water to form:
\[ \text{CH}_3\text{COONa} \rightarrow \text{CH}_3\text{COO}^- + \text{Na}^+ \]

This means that additional acetate ions (CH₃COO⁻) are introduced into the solution.

### Step 3: Apply the Common Ion Effect
The presence of additional acetate ions (CH₃COO⁻) from sodium acetate shifts the equilibrium of the acetic acid dissociation reaction to the left, according to Le Chatelier's principle. This is known as the common ion effect:
\[ \text{CH}_3\text{COOH} \rightleftharpoons \text{CH}_3\text{COO}^- + \text{H}^+ \]
With more acetate ions in the solution, the equilibrium shifts to suppress the formation of H⁺ ions and CH₃COOH, thus reducing the dissociation of acetic acid.

### Step 4: Conclusion
Therefore, the dissociation of acetic acid (CH₃COOH) is suppressed by adding sodium acetate (CH₃COONa) due to the common ion effect.

### Final Answer
The dissociation of CH₃COOH is suppressed by adding **sodium acetate (CH₃COONa)**.

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