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Ionisation of NH(4) OH is supressed by t...

Ionisation of NH_(4) OH is supressed by the addition of `NH_(4)Cl` because

A

`NH_(4)CI` is a salt of WB and SA

B

`NH_(4)CI` is a salt of strong base and weak acid

C

Of the common ion effect of `NH_(4)^(+)` ion

D

None of the above

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To solve the question regarding why the ionization of NH₄OH is suppressed by the addition of NH₄Cl, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Ionization of NH₄OH**: - Ammonium hydroxide (NH₄OH) is a weak electrolyte and ionizes in solution to form ammonium ions (NH₄⁺) and hydroxide ions (OH⁻): \[ \text{NH}_4\text{OH} \rightleftharpoons \text{NH}_4^+ + \text{OH}^- \] 2. **Effect of Adding NH₄Cl**: - When NH₄Cl is added to the solution, it is a strong electrolyte and completely dissociates into its ions: \[ \text{NH}_4\text{Cl} \rightarrow \text{NH}_4^+ + \text{Cl}^- \] - This addition increases the concentration of NH₄⁺ ions in the solution. 3. **Common Ion Effect**: - The presence of a common ion (NH₄⁺ in this case) affects the equilibrium of the ionization of NH₄OH. According to Le Chatelier's principle, if the concentration of one of the products (NH₄⁺) is increased, the equilibrium will shift to the left to counteract this change: \[ \text{NH}_4\text{OH} \rightleftharpoons \text{NH}_4^+ + \text{OH}^- \] - Thus, the ionization of NH₄OH is suppressed. 4. **Equilibrium Constant**: - The equilibrium constant (K) for the ionization of NH₄OH is given by: \[ K = \frac{[\text{NH}_4^+][\text{OH}^-]}{[\text{NH}_4\text{OH}]} \] - With the addition of NH₄Cl, the concentration of NH₄⁺ increases, which means to maintain the value of K constant, the concentration of OH⁻ must decrease, leading to less ionization of NH₄OH. 5. **Conclusion**: - Therefore, the ionization of NH₄OH is suppressed by the addition of NH₄Cl due to the common ion effect of NH₄⁺ ions. ### Final Answer: The ionization of NH₄OH is suppressed by the addition of NH₄Cl because of the common ion effect of NH₄⁺ ions. ---
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