`{:("List - I","List - II "),("(Salt)",(k_(1) = 10^(-2) k_(2) = 10^(-7))),((A) NaHSO_(3),(P)"Acidic solution "),((B) Na_(2)HPO_(3),(Q)"alkaline solution "),((C) NaH_(2)PO_(3),(R)"pH independent on concentration "),((D) Al(NO_(3))_(3),(S) "Amphoteric salt "):}`

Answer

To solve the problem of matching the salts from List - I with their corresponding characteristics from List - II, we will analyze each salt one by one based on their acidic or basic nature and their behavior in solution.

### Step-by-Step Solution:

1. **Identify the nature of NaHSO₃:**
- NaHSO₃ (sodium bisulfite) dissociates in water to form Na⁺ and HSO₃⁻ ions.
- HSO₃⁻ can act as a weak acid (donating H⁺) and also as a weak base (accepting H⁺).
- Therefore, NaHSO₃ is **amphoteric** and can lead to an **acidic solution** due to the presence of HSO₃⁻.
- **Match:** (A) NaHSO₃ → (P) "Acidic solution" and (S) "Amphoteric salt".

2. **Identify the nature of Na₂HPO₃:**
- Na₂HPO₃ (disodium hydrogen phosphite) dissociates to form Na⁺ and HPO₃²⁻ ions.
- HPO₃²⁻ can act as a weak base, leading to a basic (alkaline) solution.
- **Match:** (B) Na₂HPO₃ → (Q) "Alkaline solution".

3. **Identify the nature of NaH₂PO₃:**
- NaH₂PO₃ (sodium dihydrogen phosphite) dissociates to form Na⁺ and H₂PO₃⁻ ions.
- H₂PO₃⁻ can act as a weak acid, but it can also exhibit amphoteric behavior.
- It can lead to a basic solution due to its weak acid nature, but it can also behave as an amphoteric salt.
- **Match:** (C) NaH₂PO₃ → (R) "pH independent on concentration" and (S) "Amphoteric salt".

4. **Identify the nature of Al(NO₃)₃:**
- Al(NO₃)₃ (aluminum nitrate) dissociates to form Al³⁺ and NO₃⁻ ions.
- Al³⁺ is a cation that can hydrolyze to form H⁺ ions, leading to an acidic solution.
- **Match:** (D) Al(NO₃)₃ → (P) "Acidic solution".

### Final Matching:
- (A) NaHSO₃ → (P) "Acidic solution" and (S) "Amphoteric salt".
- (B) Na₂HPO₃ → (Q) "Alkaline solution".
- (C) NaH₂PO₃ → (R) "pH independent on concentration" and (S) "Amphoteric salt".
- (D) Al(NO₃)₃ → (P) "Acidic solution".

### Summary of Matches:
- A → P, S
- B → Q
- C → R, S
- D → P