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Why only As^(+3) gets precipitated as ...

Why only `As^(+3)` gets precipitated as `As_(2) S_(3)` and not `Zn^(2+)` as ZnS when `H_(2)`S is passed through an acidic solution containing `As^(+3) and Zn^(+2)`?

A

Solubility product of `As_(2) S_(3)` is less than that of ZnS

B

Enough `As^(+3)` are present in acidie medium

C

Zinc salt does not ionise in acidic medium

D

Solubility product changes in presence of an acid.

Text Solution

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The correct Answer is:
To understand why only \( \text{As}^{3+} \) gets precipitated as \( \text{As}_2\text{S}_3 \) and not \( \text{Zn}^{2+} \) as \( \text{ZnS} \) when \( \text{H}_2\text{S} \) is passed through an acidic solution containing both ions, we need to analyze the solubility products (Ksp) of the respective sulfides. ### Step-by-Step Solution: 1. **Identify the Ions in Solution**: The solution contains \( \text{As}^{3+} \) and \( \text{Zn}^{2+} \) ions. 2. **Understanding the Precipitation Reaction**: When \( \text{H}_2\text{S} \) is introduced into the solution, it can react with metal ions to form their respective sulfides: - \( \text{As}^{3+} + \text{H}_2\text{S} \rightarrow \text{As}_2\text{S}_3 \) (precipitate) - \( \text{Zn}^{2+} + \text{H}_2\text{S} \rightarrow \text{ZnS} \) (potential precipitate) 3. **Solubility Product (Ksp) Concept**: The precipitation of a salt occurs when the ionic product of the ions exceeds the solubility product (Ksp) of that salt. - For \( \text{As}_2\text{S}_3 \), the Ksp is relatively low. - For \( \text{ZnS} \), the Ksp is higher compared to that of \( \text{As}_2\text{S}_3 \). 4. **Comparison of Ksp Values**: - The Ksp of \( \text{As}_2\text{S}_3 \) is less than that of \( \text{ZnS} \). This means that \( \text{As}_2\text{S}_3 \) is less soluble in water compared to \( \text{ZnS} \). 5. **Ionic Product Calculation**: When \( \text{H}_2\text{S} \) is added, the ionic product for \( \text{As}^{3+} \) and \( \text{S}^{2-} \) ions will exceed the Ksp of \( \text{As}_2\text{S}_3 \) first, leading to its precipitation. - The ionic product for \( \text{Zn}^{2+} \) and \( \text{S}^{2-} \) ions does not exceed the Ksp of \( \text{ZnS} \) under the same conditions. 6. **Conclusion**: Therefore, \( \text{As}^{3+} \) precipitates as \( \text{As}_2\text{S}_3 \) because its Ksp is lower than that of \( \text{ZnS} \), which remains soluble in the solution. ### Final Answer: Only \( \text{As}^{3+} \) gets precipitated as \( \text{As}_2\text{S}_3 \) because the Ksp of \( \text{As}_2\text{S}_3 \) is lower than that of \( \text{ZnS} \), allowing \( \text{As}^{3+} \) to exceed its Ksp and precipitate, while \( \text{Zn}^{2+} \) remains in solution.
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