In an experiment of simple pendulum, the errors in the measurement of length of the pendulum `(L)` and time period `(T)` are `3%` and `2%` respectively. The maximum percentage error in the value of `L//T^(2)` is

Explanation

Maximum percentage error in the value of `L/(T^2) = ((DeltaL)/(L) xx 100) + 2((DeltaT)/(T) xx 100)`
`= 3 + (2xx2) = 3+4 = 7%`