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Two resistors of resistances R1 = 100 pm...

Two resistors of resistances `R_1 = 100 pm 3` ohm and `R_2 = 200 pm 4 ` ohm are connected (a) in series , (b) in parrallel. Find the equivalent resistance of the (a) series combination , (b) parallel combination . Use for (a) the relation `R = R_1 + R_2 and ` for (b) `1/R = 1/(R_1) + 1/(R_2) and (DeltaR')/(R^(,2)) = (DeltaR_1)/(R_1^2) + (DeltaR_2)/(R_2^2)`

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To solve the problem of finding the equivalent resistance of two resistors \( R_1 = 100 \pm 3 \) ohms and \( R_2 = 200 \pm 4 \) ohms in both series and parallel combinations, we will follow these steps: ### Part (a): Series Combination 1. **Write the formula for equivalent resistance in series**: \[ R = R_1 + R_2 \] ...
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AAKASH SERIES-UNITS AND MEASUREMENTS-EXERCISE -3
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  3. The length of a metallic sheet is measured as 10.0 cm using a metre sc...

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  18. In a simple pendulum experiment, length is measured as 31.4 cm with an...

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  19. Figure shows two capacitors of capacitance 2muF and 4muF and a cell of...

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