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A body projected up reaches a point A in...

A body projected up reaches a point A in its path at the end of 4th second and reaches the ground after 5 seconds from the start. The height of A above the ground is `(g=10 "m/s"^2)`

A

19.6 m

B

30.6 m

C

11 m

D

20 m

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The correct Answer is:
To solve the problem step by step, we need to analyze the motion of the body projected upwards and determine the height of point A above the ground. ### Step 1: Understand the motion The body is projected upwards and reaches point A at the end of 4 seconds. It then takes a total of 5 seconds to reach the ground. This means it spends 4 seconds going up and 1 second coming down after reaching the highest point. ### Step 2: Determine the time of ascent and descent - Time to reach point A = 4 seconds - Total time of flight = 5 seconds - Time to reach the maximum height = (Total time - Time to reach point A) = 5 seconds - 4 seconds = 1 second ### Step 3: Calculate the initial velocity (u) At the maximum height, the final velocity (v) is 0. We can use the equation of motion: \[ v = u - g t \] Where: - \( v = 0 \) (at the maximum height) - \( g = 10 \, \text{m/s}^2 \) (acceleration due to gravity) - \( t = 2.5 \, \text{seconds} \) (half of the total time of flight) Substituting the values: \[ 0 = u - 10 \times 2.5 \] \[ u = 10 \times 2.5 = 25 \, \text{m/s} \] ### Step 4: Calculate the maximum height (H) Using the formula for maximum height: \[ H = \frac{u^2}{2g} \] Substituting the values: \[ H = \frac{25^2}{2 \times 10} \] \[ H = \frac{625}{20} = 31.25 \, \text{m} \] ### Step 5: Calculate the height of point A (x) The body reaches point A after 4 seconds. The time taken to reach point A from the maximum height is: \[ t = 4 \, \text{seconds} - 2.5 \, \text{seconds} = 1.5 \, \text{seconds} \] Using the equation of motion to find the distance fallen from the maximum height to point A: \[ x = H - \frac{1}{2} g t^2 \] Substituting the values: \[ x = 31.25 - \frac{1}{2} \times 10 \times (1.5)^2 \] \[ x = 31.25 - \frac{1}{2} \times 10 \times 2.25 \] \[ x = 31.25 - 11.25 \] \[ x = 20 \, \text{m} \] ### Conclusion The height of point A above the ground is \( 20 \, \text{m} \).
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AAKASH SERIES-MOTION IN A STRAIGHT LINE -EXERCISE -II
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