A projectile shot at angles of `45^(@)` above the horizontal strikes a building 30 m away at a point 15 m above the point of projection. Find : (a) the speed of projection . (b) the magnitude and direction of velocity of projectile when it strikes the building .

Explanation

To solve the problem step by step, we will break it down into two parts: (a) finding the speed of projection and (b) finding the magnitude and direction of the velocity of the projectile when it strikes the building.

### Step-by-Step Solution

**Given Data:**
- Angle of projection, \( \theta = 45^\circ \)
- Horizontal distance to the building, \( x = 30 \, \text{m} \)
- Vertical height of the projectile when it strikes the building, \( y = 15 \, \text{m} \)
...