Mention the direction of motion of the projectile at the point of its maximum height .

For a projectile 'R' is range and 'H' is maximum height

The horizontal range of a projectile is R and the maximum height attained by it is H. A strong wind now begins to below in the direction of motion of the projectile, giving it a constant horizontal acceleration =g//2 . Under the same conditions of projection. Find the horizontal range of the projectile.

If the equation of motion of a projectile is y=3x -1/8 x^(2) the range and maximum height are respectively (y and x are in metres)

In a projectile motion the velocity

In a projectile motion the velocity

Projectile Motion

Find the angle of projection of a projectile for which the horizontal range and maximum height are equal.

Find the angle of projection of a projectile for which the horizontal range and maximum height are equal.

A particle of mass m is projected with a velocity v making an angle of 45^@ with the horizontal. The magnitude of the angular momentum of the projectile abut the point of projection when the particle is at its maximum height h is.

A projectile is thrown with a velocity vec v _(0) = 3hati + 4 hatj ms ^(-1) where hat I and hatj are the unit vectors along the horizontal and vertical directions respectively. The speed of the projectile at the highest point of its motion in ms ^(-1) is