Two bodies are thrown at angles `theta` and (90- `theta` ) from the same point with same velocity `25ms^(-1)`. If the difference between their maximum heights is 15m, the respective maximum heights are (g=10 `ms^(-2)`)

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the problem
We have two bodies thrown at angles \( \theta \) and \( 90 - \theta \) with the same initial velocity \( u = 25 \, \text{m/s} \). We need to find their maximum heights \( h_1 \) and \( h_2 \) given that the difference between their maximum heights is 15 m.

### Step 2: Write the formula for maximum height
The maximum height \( h \) attained by a projectile is given by the formula:
\[
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