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A and B are the numerical values of a ph...

A and B are the numerical values of a physical quantity and C and D are its units in two systems of mesurement . If C > D, then

A

`A gt B`

B

A less than B

C

A = B

D

A & B cannot be related

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the relationship between the numerical values of a physical quantity and its units in two different systems of measurement. Let's break it down step by step: ### Step 1: Understand the relationship between numerical values and units A physical quantity can be expressed as: \[ \text{Physical Quantity} = \text{Numerical Value} \times \text{Unit} \] Let’s denote: - \( A \) as the numerical value of the physical quantity in the first system, - \( B \) as the numerical value of the physical quantity in the second system, - \( C \) as the unit in the first system, - \( D \) as the unit in the second system. ### Step 2: Establish the relationship between the two systems From the definition of physical quantities, we can write: \[ A \times C = B \times D \] This equation indicates that the physical quantity remains the same regardless of the system of measurement used. ### Step 3: Rearranging the equation Rearranging the equation gives us: \[ \frac{A}{B} = \frac{D}{C} \] ### Step 4: Analyze the given condition We are given that \( C > D \). This implies that: \[ \frac{D}{C} < 1 \] ### Step 5: Conclude the relationship between A and B Since \( \frac{A}{B} = \frac{D}{C} \) and \( \frac{D}{C} < 1 \), it follows that: \[ \frac{A}{B} < 1 \] This means: \[ A < B \] ### Final Conclusion Thus, if \( C > D \), then we conclude that: \[ A < B \] ### Answer The correct option is: **A is less than B.** ---
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