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Boltzman constant and Plank's constant d...

Boltzman constant and Plank's constant differ in the dimensions of

A

Mass and Time

B

Length and Time

C

Length and Mass

D

Time and temperature

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The correct Answer is:
To determine how Boltzmann's constant and Planck's constant differ in dimensions, we need to analyze their definitions and the formulas in which they appear. ### Step-by-Step Solution: 1. **Identify the Constants:** - Boltzmann's constant (k) is used in thermodynamics, particularly in the ideal gas law. - Planck's constant (h) is used in quantum mechanics, particularly in the energy of photons. 2. **Write Down the Relevant Formulas:** - For Boltzmann's constant, we can use the ideal gas law: \[ PV = nRT \] Rearranging gives: \[ k = \frac{PV}{nT} \] - For Planck's constant, the energy of a photon is given by: \[ E = h\nu \] Rearranging gives: \[ h = \frac{E}{\nu} \] 3. **Determine the Dimensions:** - For Boltzmann's constant (k): - Pressure (P) has dimensions of \([M L^{-1} T^{-2}]\). - Volume (V) has dimensions of \([L^3]\). - Number of moles (n) is dimensionless. - Temperature (T) has dimensions of \([\Theta]\) (where \(\Theta\) is the dimension of temperature). - Thus, the dimensions of k can be calculated as: \[ [k] = \frac{[P][V]}{[n][T]} = \frac{[M L^{-1} T^{-2}][L^3]}{[T]} = [M L^2 T^{-2} \Theta^{-1}] \] - For Planck's constant (h): - Energy (E) has dimensions of \([M L^2 T^{-2}]\). - Frequency (\(\nu\)) has dimensions of \([T^{-1}]\). - Thus, the dimensions of h can be calculated as: \[ [h] = \frac{[E]}{[\nu]} = \frac{[M L^2 T^{-2}]}{[T^{-1}]} = [M L^2 T^{-1}] \] 4. **Compare the Dimensions:** - Boltzmann's constant: \([M L^2 T^{-2} \Theta^{-1}]\) - Planck's constant: \([M L^2 T^{-1}]\) 5. **Identify the Differences:** - The dimensions of mass (M) and length (L) are the same for both constants. - The time dimension (T) differs: Boltzmann's constant has \(T^{-2}\) while Planck's constant has \(T^{-1}\). - The temperature dimension (\(\Theta\)) is present in Boltzmann's constant but absent in Planck's constant. 6. **Conclusion:** - The difference in dimensions between Boltzmann's constant and Planck's constant is due to the presence of temperature (\(\Theta\)) in Boltzmann's constant and the different powers of time (T). ### Final Answer: Boltzmann's constant and Planck's constant differ in the dimensions of time and temperature.
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AAKASH SERIES-UNITS AND MEASUREMENT-EXERCISE - I
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  2. The set of quantities which can form a group of fundamental quantities...

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  3. Boltzman constant and Plank's constant differ in the dimensions of

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  7. The pair of vector quantities haivng the same dimensions is

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  8. Planck constant has the same dimensions as

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  10. The correct statement is :

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  11. SI unit and CGS unit of certain quantity vary by 10^3 times.That quant...

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  12. The pair of physical quantities having the same dimensional formula ar...

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  18. Find SI units of thermal resistance.

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