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SI unit and CGS unit of certain quantity...

SI unit and CGS unit of certain quantity vary by `10^3` times.That quantity is

A

Boltzmann constant

B

Gravitational constant

C

Planck's constant

D

Angular momentum

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The correct Answer is:
To solve the problem of identifying which physical quantity has SI and CGS units that vary by \(10^3\) times, we will analyze the given quantities: Boltzmann constant (kB), gravitational constant (G), Planck's constant (h), and angular momentum (L). We will derive their dimensional formulas and calculate the variation between their SI and CGS units. ### Step-by-Step Solution: 1. **Identify the quantities and their dimensions**: - **Boltzmann constant (kB)**: The dimensional formula is \( [M^1 L^2 T^{-2} K^{-1}] \). - **Gravitational constant (G)**: The dimensional formula is \( [M^{-1} L^3 T^{-2}] \). - **Planck's constant (h)**: The dimensional formula is \( [M^1 L^2 T^{-1}] \). - **Angular momentum (L)**: The dimensional formula is \( [M^1 L^2 T^{-1}] \). 2. **Identify the units in SI and CGS**: - **Mass**: - SI: kilogram (kg) - CGS: gram (g) - \(1 \text{ kg} = 10^3 \text{ g}\) - **Length**: - SI: meter (m) - CGS: centimeter (cm) - \(1 \text{ m} = 10^2 \text{ cm}\) - **Time**: - Both SI and CGS use seconds (s). - **Temperature**: - Both SI and CGS use Kelvin (K). 3. **Calculate the conversion factors for each quantity**: - For **Boltzmann constant (kB)**: \[ \text{SI unit} = kg \cdot m^2 \cdot K^{-1} \quad \text{and} \quad \text{CGS unit} = g \cdot cm^2 \cdot K^{-1} \] \[ \text{Conversion} = 10^3 \cdot (10^2)^2 = 10^3 \cdot 10^4 = 10^7 \] - For **Gravitational constant (G)**: \[ \text{SI unit} = \frac{kg \cdot m^3}{s^2} \quad \text{and} \quad \text{CGS unit} = \frac{g \cdot cm^3}{s^2} \] \[ \text{Conversion} = \frac{1}{10^3} \cdot (10^2)^3 = 10^{-3} \cdot 10^6 = 10^3 \] - For **Planck's constant (h)**: \[ \text{SI unit} = kg \cdot m^2 \cdot s^{-1} \quad \text{and} \quad \text{CGS unit} = g \cdot cm^2 \cdot s^{-1} \] \[ \text{Conversion} = 10^3 \cdot (10^2)^2 = 10^3 \cdot 10^4 = 10^7 \] - For **Angular momentum (L)**: \[ \text{SI unit} = kg \cdot m^2 \cdot s^{-1} \quad \text{and} \quad \text{CGS unit} = g \cdot cm^2 \cdot s^{-1} \] \[ \text{Conversion} = 10^3 \cdot (10^2)^2 = 10^3 \cdot 10^4 = 10^7 \] 4. **Conclusion**: - The only quantity that has SI and CGS units varying by \(10^3\) times is the **gravitational constant (G)**. ### Final Answer: The quantity whose SI unit and CGS unit vary by \(10^3\) times is the **gravitational constant (G)**.
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AAKASH SERIES-UNITS AND MEASUREMENT-EXERCISE - I
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