Home
Class 12
PHYSICS
The dimensional formula of the physical ...

The dimensional formula of the physical quantity whose S.I. unit is farad is

A

`ML^(2)T^(3)I^(-2)`

B

`M^(-1)L^(-3)T^(4)I^(2)`

C

`M^(-1)L^(-2)T^(4)I^(2)`

D

`M^(-1)L^(-2)T^(3)I^(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the dimensional formula of the physical quantity whose SI unit is farad (F), we need to understand what capacitance is and how it relates to charge and voltage. ### Step-by-Step Solution: 1. **Identify the Physical Quantity**: The SI unit of capacitance is the farad (F). Capacitance (C) is defined as the ability of a system to store charge per unit voltage. 2. **Write the Formula for Capacitance**: The formula for capacitance is given by: \[ C = \frac{Q}{V} \] where \( Q \) is the charge and \( V \) is the voltage. 3. **Express Voltage in Terms of Work**: Voltage (or potential difference) can be expressed as: \[ V = \frac{W}{Q} \] where \( W \) is the work done. 4. **Substituting Voltage into the Capacitance Formula**: Substituting the expression for voltage into the capacitance formula gives: \[ C = \frac{Q}{\frac{W}{Q}} = \frac{Q^2}{W} \] 5. **Dimensional Formula for Charge (Q)**: Charge is defined as current (I) multiplied by time (t): \[ Q = I \cdot t \] The dimensional formula for current (I) is \( A \) (amperes), so: \[ [Q] = [I][t] = [A][T] = A \cdot T \] Therefore, the dimensional formula for \( Q^2 \) is: \[ [Q^2] = [A^2][T^2] \] 6. **Dimensional Formula for Work (W)**: Work is defined as force (F) multiplied by distance (s): \[ W = F \cdot s \] The dimensional formula for force is: \[ [F] = [M][L][T^{-2}] \] Therefore, the dimensional formula for work is: \[ [W] = [M][L][T^{-2}] \cdot [L] = [M][L^2][T^{-2}] \] 7. **Combine the Dimensional Formulas**: Now substituting the dimensional formulas into the capacitance formula: \[ [C] = \frac{[Q^2]}{[W]} = \frac{[A^2][T^2]}{[M][L^2][T^{-2}]} \] 8. **Simplifying the Expression**: This simplifies to: \[ [C] = \frac{A^2 T^2}{M L^2 T^{-2}} = A^2 T^4 M^{-1} L^{-2} \] 9. **Final Dimensional Formula**: Thus, the final dimensional formula for capacitance (and hence for farad) is: \[ [C] = M^{-1} L^{-2} T^4 A^2 \] ### Conclusion: The dimensional formula of the physical quantity whose SI unit is farad is: \[ [M^{-1} L^{-2} T^4 A^2] \]
Promotional Banner

Topper's Solved these Questions

  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise EXERCISE - II|61 Videos
  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos
  • UNITS AND MEASUREMENT

    AAKASH SERIES|Exercise PRACTICE EXERCISE|45 Videos
  • SEMICONDUCTOR DEVICES

    AAKASH SERIES|Exercise EXERCISE - III|3 Videos
  • UNITS AND MEASUREMENTS

    AAKASH SERIES|Exercise EXERCISE -3|66 Videos

Similar Questions

Explore conceptually related problems

Dimensional formula of the physical quantity, resistance is

The dimensional formula of the product of two physical quantities P and Q is ML^2 T^(-2) . The dimensional formula of P//Q is ML^0 T^(-2) . Then what are the units of physical quantities P and Q.

The dimensional formula of physical quantity is [M^(a)L^(b)T^(c)] .Then that physical quantity is

Name the physical quantity whose unit is tesla. Hence define a tesla.

Consider following statement :- (A) any physical quantity may have more one unit. (B) Any physical quantity have only one dimensional formula (C ) More than one physical quantities may have same dimension. (D) We can add & subtract only those expression having same dimension. Number of correct statements is :-

Name a derived physical quantity with its Sl unit.

Dimensional formula of the product of the two physical quantities P and Q is ML^(2)T^(-2) , the dimesional formula of P//Q is MT^(-2) . P and Q respectively are

The dimensional formula for a physical quantity x is [M^(-1) L^(3) T^(-2) ] . The errors in measuring the quantities M , L , and T, respectively are 2%, 3% , and 4% . The maximum percentage of error that occurs in measuring the quantity x is

The dimensional formula of product and quotient of two physical quantities A and B are given by [AB]=[ML^(2)T^(-2)], [A/B]=[MT^(-2)] . The quantities A and B respectively are

The dimensional formula for stefan's constant 's' is