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(he)/(4 pi m) has the same dimensions as...

`(he)/(4 pi m)` has the same dimensions as (h = Planck's constant , e = charge , m = mass.)

A

Magnetic moment

B

Magnetic induction

C

Angular moment

D

Pole strength

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The correct Answer is:
To solve the problem where we need to find the dimensions of the expression \((he)/(4 \pi m)\), we will break it down step by step. ### Step 1: Identify the dimensions of each component 1. **Planck's constant (h)**: The dimension of Planck's constant is given by the formula: \[ [h] = [Energy] \times [Time] = [M L^2 T^{-2}] \times [T] = [M L^2 T^{-1}] \] 2. **Charge (e)**: The dimension of charge can be expressed as: \[ [e] = [Current] \times [Time] = [A] \times [T] \] where \(A\) is the dimension of electric current. 3. **Mass (m)**: The dimension of mass is simply: \[ [m] = [M] \] ### Step 2: Combine the dimensions Now we can substitute the dimensions into the expression \((he)/(4 \pi m)\): \[ \frac{he}{4 \pi m} = \frac{[h] \cdot [e]}{[m]} \] Substituting the dimensions we found: \[ = \frac{[M L^2 T^{-1}] \cdot [A T]}{[M]} \] ### Step 3: Simplify the expression Now we simplify the expression: \[ = \frac{[M L^2 T^{-1} A T]}{[M]} = [L^2 T^{0} A] = [L^2 A] \] ### Step 4: Identify the physical quantity The dimension \([L^2 A]\) corresponds to the dimension of magnetic moment. Therefore, the expression \((he)/(4 \pi m)\) has the same dimensions as magnetic moment. ### Conclusion Thus, the answer to the question is that \((he)/(4 \pi m)\) has the same dimensions as **magnetic moment**. ---
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AAKASH SERIES-UNITS AND MEASUREMENT-EXERCISE - I
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  3. (he)/(4 pi m) has the same dimensions as (h = Planck's constant , e =...

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  5. The dimensional formula for the capacitance of a capacitor is

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  6. The SI unit of magneitc flux is

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  7. The physical quantities not having same dimensions are

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  8. Fundamental unit out of the following is

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  9. The ratio of SI unit of CGS unit of a plysical constant is 10^(7). Tha...

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  10. Electron volt is the unit of

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  11. The unit of reduction factor of tangent galvanometer

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  12. The SI unit of magnetic permebility is

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  13. ML^(2)T^(-2)I^(-2) is the dimensional formula for

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  14. Magnetic induction and magnetic flux differ in the dimensions of

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  16. Let [epsilon(0)] denote the dimensional formula of the permittivity of...

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  18. The dimensional formula for magnetic flux is

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  19. The unit and dimensions of impedance in terms of charge Q are

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  20. If energy E, velocity V and time T are taken as fundamental units, the...

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