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Turpentine oil is flowing through a tube...

Turpentine oil is flowing through a tube of length `L` and radius `r`. The pressure difference between the two ends of the tube is `p` , the viscosity of the coil is given by `eta = (p (r^(2) - x^(2)))/(4 vL)`, where `v` is the velocity of oil at a distance `x` from the axis of the tube. From this relation, the dimensions of viscosity `eta` are

A

`[M^0L^0T^0]`

B

`[MLT^(-1)]`

C

`[ML^2T^(-2)]`

D

`[ML^(-1)T^(-1)]`

Text Solution

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The correct Answer is:
D
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AAKASH SERIES-UNITS AND MEASUREMENT-EXERCISE - I
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