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If the unit of force were 10N, that of p...

If the unit of force were 10N, that of power were 1 MW and that of time were 1 millisecond then the unit of length would be 

A

`1 m`

B

`100 m`

C

`10^3 m`

D

`10^(-2) m`

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The correct Answer is:
To solve the problem, we need to find the unit of length given the units of force, power, and time. We will use the relationship between power, force, and velocity. ### Step-by-Step Solution: 1. **Understand the relationship between power, force, and velocity**: The formula for power (P) is given by: \[ P = F \cdot v \] where \( F \) is the force and \( v \) is the velocity. Velocity can also be expressed as distance (length, \( L \)) divided by time (\( t \)): \[ v = \frac{L}{t} \] Therefore, we can rewrite the power equation as: \[ P = F \cdot \frac{L}{t} \] 2. **Rearranging the equation**: From the above equation, we can express length \( L \) as: \[ L = \frac{P \cdot t}{F} \] 3. **Substituting the given values**: We are given: - Unit of force \( F = 10 \, \text{N} \) - Unit of power \( P = 1 \, \text{MW} = 10^6 \, \text{W} \) - Unit of time \( t = 1 \, \text{ms} = 10^{-3} \, \text{s} \) Now substituting these values into the equation for \( L \): \[ L = \frac{10^6 \, \text{W} \cdot 10^{-3} \, \text{s}}{10 \, \text{N}} \] 4. **Calculating the length**: Simplifying the equation: \[ L = \frac{10^6 \cdot 10^{-3}}{10} \] \[ L = \frac{10^3}{10} = 10^2 \, \text{m} = 100 \, \text{m} \] 5. **Conclusion**: Therefore, the unit of length is \( 100 \, \text{meters} \). ### Final Answer: The unit of length is **100 meters**. ---
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AAKASH SERIES-UNITS AND MEASUREMENT-EXERCISE - II
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  3. If the unit of force were 10N, that of power were 1 MW and that of tim...

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  4. If the unit of power is million erg/minute, the unit of force is 1000 ...

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