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If length and breadth of a plane are (40...

If length and breadth of a plane are `(40 + 0.2)` and `(30 +- 0.1)` cm, the absolute error in measurement of area is

A

`10 cm^2`

B

`8 cm^2`

C

`9 cm^2`

D

`7 cm^2`

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The correct Answer is:
To find the absolute error in the measurement of the area of a rectangle given its length and breadth with associated uncertainties, we can follow these steps: ### Step 1: Identify the given values - Length (L) = \(40 \pm 0.2\) cm - Breadth (B) = \(30 \pm 0.1\) cm ### Step 2: Calculate the actual area The area (A) of a rectangle is given by the formula: \[ A = L \times B \] Substituting the values: \[ A = 40 \, \text{cm} \times 30 \, \text{cm} = 1200 \, \text{cm}^2 \] ### Step 3: Determine the relative errors The relative error in the area can be calculated using the formula: \[ \frac{\Delta A}{A} = \frac{\Delta L}{L} + \frac{\Delta B}{B} \] Where: - \(\Delta L = 0.2\) cm (absolute error in length) - \(\Delta B = 0.1\) cm (absolute error in breadth) ### Step 4: Substitute the values into the formula Now we can substitute the values into the relative error formula: \[ \frac{\Delta A}{1200} = \frac{0.2}{40} + \frac{0.1}{30} \] ### Step 5: Calculate each term Calculating the first term: \[ \frac{0.2}{40} = 0.005 \] Calculating the second term: \[ \frac{0.1}{30} \approx 0.00333 \] ### Step 6: Add the relative errors Now, we add these two relative errors: \[ \frac{\Delta A}{1200} = 0.005 + 0.00333 \approx 0.00833 \] ### Step 7: Calculate the absolute error in area To find the absolute error in area (\(\Delta A\)), we multiply the relative error by the actual area: \[ \Delta A = A \times \frac{\Delta A}{A} = 1200 \times 0.00833 \approx 10 \, \text{cm}^2 \] ### Conclusion The absolute error in the measurement of the area is approximately \(10 \, \text{cm}^2\). ---
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