The distance travelled by a body is 107.25 m in time 1.5 s. The velocity with correct significant figures is

Options

A. 71.5
B. 71
C. 71.5
D. `72.0`

Answer

To find the velocity of the body with the correct significant figures, we will follow these steps:

### Step 1: Identify the given values
We have the distance \( d = 107.25 \, \text{m} \) and the time \( t = 1.5 \, \text{s} \).

### Step 2: Use the formula for velocity
The formula for velocity \( v \) is given by:
\[ v = \frac{d}{t} \]

### Step 3: Substitute the values into the formula
Substituting the values we have:
\[ v = \frac{107.25 \, \text{m}}{1.5 \, \text{s}} \]

### Step 4: Perform the calculation
Calculating the above expression:
\[ v = \frac{107.25}{1.5} = 71.5 \, \text{m/s} \]

### Step 5: Determine the significant figures
Now, we need to express the velocity with the correct significant figures. The distance \( 107.25 \, \text{m} \) has 5 significant figures, while the time \( 1.5 \, \text{s} \) has 2 significant figures. According to the rules of significant figures in multiplication and division, the result should be expressed with the same number of significant figures as the measurement with the least significant figures.

### Step 6: Round the result to the correct number of significant figures
Since the time has 2 significant figures, we round \( 71.5 \, \text{m/s} \) to 2 significant figures:
\[ v = 72 \, \text{m/s} \]

### Final Answer
Thus, the velocity with the correct significant figures is:
\[ \boxed{72 \, \text{m/s}} \]

---