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9.27//41= (consider significant digits)...

`9.27//41`= (consider significant digits)

A

`0.226 `

B

`0.23`

C

`0.2`

D

`0.2261`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem \( \frac{9.27}{41} \) and consider significant digits, we will follow these steps: ### Step 1: Identify Significant Figures First, we need to identify the number of significant figures in each number involved in the calculation. - The number 9.27 has **three significant figures** (9, 2, and 7). - The number 41 has **two significant figures** (4 and 1). ### Step 2: Perform the Division Now, we perform the division: \[ \frac{9.27}{41} = 0.2263170732 \ldots \] ### Step 3: Determine the Significant Figures for the Result Since we are required to consider significant figures, we must round our result to the least number of significant figures from the numbers we used in the calculation. The number with the least significant figures is 41, which has **two significant figures**. ### Step 4: Round the Result Now we round 0.2263170732 to two significant figures: - The first two significant figures in 0.226 are 2 and 2. - To round it, we look at the third significant figure, which is 6. Since 6 is greater than 5, we round up the last significant figure (2) to 3. Thus, rounding 0.226 gives us: \[ 0.23 \] ### Final Answer The final answer, considering significant figures, is: \[ \boxed{0.23} \] ---
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AAKASH SERIES-UNITS AND MEASUREMENT-PRACTICE EXERCISE
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  2. The error in the measument of radius of a sphere is 0.4% . The relativ...

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  3. If L1 = 2.02 m pm 0.01 m , L2 = 1.02 m pm 0.01 m , determine L1 + 2L2

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  4. If the length of a cylinder is measured to be 50 cm with an error of ...

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  5. The length of a cylinder is measured as 5 cm using a vernier calipers ...

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  6. A body travels uniformly a distance of (20.0 pm 0.2)m in time (4.0 pm ...

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  7. Time for 20 oscillations of a pendulum is measured as t(1)=39.6" "s,...

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  8. The radius of earth is 6347 km. Its rounded off value up to two signif...

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  9. 3400 has significant figures

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  10. The number of significant figures in 0.0160 kg is

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  11. The number of significant figures in an area 2.64 xx 10^(24) m^(2) is

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  12. The distance travelled by a body is 107.25 m in time 1.5 s. The veloci...

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  13. Less accurate of the four options given below

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  14. 9.27//41= (consider significant digits)

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  15. When 57.986 is rounded off to 4 significant figures, then it becomes

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  16. The value of 44.8 - 21.235 is

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  17. The length and breadth of a rectangular object are 25.2 cm and 16.8 cm...

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  18. The value of 124.2 - 52.487 with due regard to significant places is

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  19. The value of 117.3 xx 0.0024 with due regard to significant figures is

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  20. The value of (17.5)^2 is

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