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Two vectors vecA and vecB have equal mag...

Two vectors `vecA` and `vecB` have equal magnitudes. The magnitude of `(vecA+vecB)` is n times the magnitude of `(vecA-vecB)`. The angle between `vecA` and `vecB` is :

Text Solution

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`|vecA + vecB| =n|vecA-vecB|`
`2A costheta/2 =n2A sintheta/2 (A=B)`
`therefore tan theta/2 =1/n, theta/2 = tan^(-1)(1/n), theta = 2tan^(-1)(1/n)`
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