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As shown in figure the tension in the ho...

As shown in figure the tension in the horizontal cord is 30 N. The weight W and tension in the string OA in Newton are :

Text Solution

Verified by Experts

Let `T_(1)` and `T_(2)` be the tensions in the strings OA and OB respectively.

According to lami.s theorem
`T_(1)/(sin 90^(@)) =T_(2)/(sin 150^(@)) =W/(sin 120^(@)) (T_(2)=30 N)`
on solving `w=30sqrt(3) N` and `T_(1) = 60 N`
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