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The maximum range of a projectile is 500...

The maximum range of a projectile is 500m. If the particle is thrown up a plane, which is inclined at an angle of `30^@` with the same speed, the distance covered by it along the inclined plane will be

Text Solution

Verified by Experts

`R_("max") =u^(2)/g`
`therefore 500 =u^(2)/g` or `u=sqrt(500 g)`
`v^(2)-u^(2) =2gs`
`rArr 0-500g =2 xx (g sin 30^(@))xx x`
`x=500 m`
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