The horizontal range and miximum height attained by a projectile are `R and H`, respectively. If a constant horizontal acceleration `a = g//4` is imparted to the projectile due to wind, then its horizontal range and maximum height will be

Explanation

`H^(1) =H` (`therefore u sin theta` remains same)
`T.=T`
`R. =u_(x) T + 1/2 aT^(2) =R + 1/2 g/4 T^(2)`
`=R + 1/8 gT^(2) =R + H`
`R^(1) =R + H`
`H^(1)=H`