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A particle is projected from the ground ...

A particle is projected from the ground with an initial speed u at an angle `theta` with the horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is

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`v_("avg") =(vecv + vecu)/2 = (u cos thetahati +(u cos thetahati + u sintheta))/2`
`v_(av) =v/2sqrt(1+3 cos^(2)theta)`
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