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Two particles move in a uniform gravitat...

Two particles move in a uniform gravitational field with an acceleration g. At the initial moment the particles were located over a tower at one point and moved with velocities `v_1 = 3m//s and v_2= 4m//s` horizontally in opposite directions. Find the distance between the particles at the moment when their velocity vectors become mutually perpendicular.

Text Solution

Verified by Experts

`t= sqrt((u_(1)u_(2))/g), x=(u_(1) + u_(2))t`

=0.48 m
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