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A vector hati + sqrt(3) hatj rotates ab...

A vector `hati + sqrt(3) hatj` rotates about its tail through an angle 60° in clockwise direction then the new vector is

A

`hati + sqrt(3)hatj`

B

`3hati - 4hatj`

C

`2hatj`

D

`2hati`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the vector given and how it transforms when rotated. ### Step 1: Identify the initial vector The initial vector is given as: \[ \mathbf{v} = \hat{i} + \sqrt{3} \hat{j} \] This means the vector has a component of 1 in the x-direction (i.e., along \(\hat{i}\)) and \(\sqrt{3}\) in the y-direction (i.e., along \(\hat{j}\)). ### Step 2: Plot the vector To visualize the vector, we can plot it on a Cartesian coordinate system: - The x-component is 1, and the y-component is \(\sqrt{3}\). - The endpoint of the vector will be at the point (1, \(\sqrt{3}\)). ### Step 3: Calculate the angle with the x-axis To find the angle \(\theta\) that the vector makes with the x-axis, we use the tangent function: \[ \tan(\theta) = \frac{\text{y-component}}{\text{x-component}} = \frac{\sqrt{3}}{1} = \sqrt{3} \] From trigonometry, we know that: \[ \theta = 60^\circ \] ### Step 4: Rotate the vector The problem states that the vector rotates clockwise by \(60^\circ\). Since the vector initially makes an angle of \(60^\circ\) with the x-axis, rotating it clockwise by \(60^\circ\) will align it with the x-axis. ### Step 5: Determine the new vector's direction After the rotation, the vector will be directed along the positive x-axis. The magnitude of the vector remains the same. ### Step 6: Calculate the magnitude of the original vector The magnitude of the original vector can be calculated as: \[ |\mathbf{v}| = \sqrt{(1)^2 + (\sqrt{3})^2} = \sqrt{1 + 3} = \sqrt{4} = 2 \] ### Step 7: Write the new vector Since the new direction is along the positive x-axis and the magnitude is 2, the new vector can be expressed as: \[ \mathbf{v}_{\text{new}} = 2 \hat{i} \] ### Final Answer Thus, the new vector after the rotation is: \[ \mathbf{v}_{\text{new}} = 2 \hat{i} \] ---
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